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2 years ago

5

Two angles that share a common endpoint and a common ray to measure of 1/4 turn

1 answer:

ElenaW [278]2 years ago

6 0

Look at https://quizlet.com/subject/term%3Aangles%20%3D%20two%20rays%20with%20a%20common%20endpoint%20form%2... and it will help you tremendously.

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there are 18 bikes in the bike rack there are four more blue bikes than yellow bikes and two less yellow bikes and green bikes h

jeyben [28]

So
green bikes:20
yellow bikes:20. but don't really understand
blue bikes:22

8 0

3 years ago

I'm confused can someone please help me out?

Anika [276]

Answer:

0.4375

Step-by-step explanation:

if F=ma that to find the acceleration then use the formula a = F/m which gives you 0.4375

<h2><u><em>**Please rate 5 give thanks and vote brainliest**</em></u></h2>

6 0

2 years ago

Two cards are drawn without replacement from a standard deck of 52 cards. What is the probability that one of the cards is red a

alukav5142 [94]

Total cards = 52
Total red cards = 26
Total black cards = 26

P(one red and one black) = P(red and then black)+ P(black and then red)
P(one red and one black) =(26/52)(26/51) + (26/52)(26/51)
P(one red and one black) = 26/51 (Answer A)

-----------------------------------------------------
Answer: 26/51 (Answer A)
-----------------------------------------------------

5 0

3 years ago

a weight lifter can lift 550 pounds. his goal is to improve by 20% during the next year. how many pounds does he want to be able

sattari [20]

The answer is 660 lbs.

Hope this helps!

7 0

2 years ago

Factorize 2a^2+7a-15

loris [4]

$\huge\bf \pink {\underline{Solution :-}}$

$2 {a}^{2} + 7a - 15$

$= 2 {a}^{2} + 10a - 3a - 15$

$= 2a(a + 5) - 3(a + 5)$

$= (a + 5)(2a - 3)$

$\sf \red{Hence, Answer \: is \: (a + 5)(2a - 3).}$

$\\$

$\bf \purple{ \underline{ Important \: Formulas \: for \: Factorization :-}}$

$• \: {a}^{2} + 2ab + {b}^{2} = {(a + b)}^{2}$

$• \: (a + b)(a - b) = {a}^{2} - {b}^{2}$

$• \: {a}^{2} - 2 ab + {b}^{2} = {(a - b)}^{2}$

$• \: {a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} = {(a + b)}^{3}$

$• \: {a}^{3} - 3 {a}^{2} b + 3a {b}^{2} - {b}^{3} = {(a - b)}^{3}$

$• \: {(a + b)}^{2} + {(a - b)}^{2} = 2( {a}^{2} + {b}^{2} )$

$• \: {(a + b)}^{2} - {(a - b)}^{2} = 4ab$

$• \: (a + b)( {a}^{2} -ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

$• \: (a - b)( {a}^{2} + ab + {b}^{2} ) = {a}^{3} - {b}^{3}$

$• \: {( \frac{a + b}{2} )}^{2} - ( {\frac{a - b}{2} } )^{2} = ab$

5 0

3 years ago

Read 2 more answers