Answer:
There are 147 students in the school.
Step-by-step explanation:
3/7 of the students are in sixth grade, 63 students are in the sixth grade.
take 63 and divide it by the numerator, 3, you get 21.
You now multiply the fraction by 21 to get the full number of students in the school.
3 * 21 = 63, 7 * 21 = 147
So 63 sixth graders out of 147 total students in the school.
Answer:
its 50 points but still answer is a
The value of a is 1/4 and the equation of the parabola is (x-2)² = (y+2)
<h3>What is a Parabola ?</h3>
A parabola is a u shaped curve. It is a plane curve whose all points are at a fixed distance form a point called focus.
(x-h)² = 4a(y-k)
It is given that the parabola goes through the point (3, -1), and the vertex is at (2, -2).
Therefore
(x -2)² = 4a(y +2)
The parabola passes through the point (3,-1)
(3-2)² = 4*a(-1+2)
1 = 4 a
a = 1/4
The equation of the parabola is
(x-2)² = (y+2)
Therefore The value of a is 1/4 and the equation of the parabola is (x-2)² = (y+2)
To know more about Parabola
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The squares here are organized in a way where one can prove the Pythagorean theorem. The Pythagorean theorem is the theorem that states that the length of one side of a right triangle, squared, plus the length of another leg of the triangle, squared, is equal to the hypotenuse squared. This is a² + b² = c². Since the areas of the squares are the squared lengths of the sides, that means that D. is the right answer.
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
