The product of a <em>complex</em> number and its conjugate is (a + i b) · (a - i b), where a and b are <em>real</em> numbers, and the result for the <em>complex</em> number 2 + i 3 is 13.
<h3>What is the multiplication of a complex number and its conjugate</h3>
Let be a <em>complex</em> number a + i b, whose conjugate is a - i b. Where a and b are <em>real</em> numbers. The product of these two numbers is:
(a + i b) · (a - i b)
Then, we proceed to obtain the result by some algebraic handling:
a · (a + i b) + (- i b) · (a + i b)
a² + i a · b - i a · b - i² b²
a² - i² b²
a² + b²
If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:
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D because one thousand nine hundred twenty divided by 8 equals two hundred and forty
Answer:
AC=9 cm
ABC is not a right angled triangle
Step-by-step explanation:
AB=8cm
BC=5cm
22=AB+BC+AC
AC=22-8-5
AC=9
since AC is the longest,
using Pythagoras theorem
AC^2=BC^2+AB^2
9^2=8^2+5^2
81=64+25
81=89
therefore, it is not a right angled triangle
Answer:
6
Step-by-step explanation: