Two hundred thirty-five and six hundred seventy-eight thousandths
Answer:
Perimeter of square Q is 49 inches.
Step-by-step explanation:
Let x be the length of side of square P and y be that of square Q.
It is given in the question that :
Also it is given that x=3.5 inches.Hence
∴ y=12.25 inches.
Perimeter of square Q is 4y = 
inches.
Answer:
Step-by-step explanation:
Given
![y = \sqrt[3] x](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%20x)
Required
Determine the average rate of change over [2,7]
This is calculated as:
In this case:
and 
So, we have:
From the table:
f(7) = 1.91
f(2) = 1.26
Answer:
j² - 5j²k - 2
Step-by-step explanation:
3j² - j²k - 6 - 4j²k - 2j² + 4
To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.
We have three groups of like terms:
The j-squares (j²), the j-squared k (j²k) and the constants (no variable).
Remember to include the negatives!
The j-squares are: 3j² ; -2j²
The j-squares k are: - j²k ; - 4j²k
The constants are: - 6 ; 4
Simplify:
3j² - j²k - 6 - 4j²k - 2j² + 4
Rearrange the polynomial by like terms
= (- j²k - 4j²k) + (3j² - 2j²) + (- 6 + 4)
Add or subtract the like terms
= (-5j²k) + (j²) + (-2)
Remove brackets and rearrange so the negative is not first
= j² + - 5j²k + - 2
Simplify where two signs are together. Adding a negative is subtraction.
= j² - 5j²k - 2 Simplified
