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Rashid [163]
3 years ago
8

Given the following polynomial find the maximum possible number of turning points. f(x)=x6+x2+x7+x12

Mathematics
1 answer:
Lesechka [4]3 years ago
8 0
If you put in descending order you get:
f(x) = x^12 + x^7 + x^6 + x^2
The highest power (n) is 12 so the maximum number of turning points is (n - 1),  12 -1 = 11
You can have 11 turning points

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Please help me ive been stuck on this question for days! Thank you
Zielflug [23.3K]
Okay, so this is basically telling you that there is no solution. You don't have to worry about there being one. You just have to justify (or explain) why there isn't one.

Basically, neither y or x is equal to anything. You couldn't make x equal to a value in y because x and y are both together in the equation and equal to numbers. 

We can always move a factor to the other side. So,

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The 6y's cancel out. So, we can't figure out what y is.

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I hope this helps! 
~kaikers


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