Given the following polynomial find the maximum possible number of turning points. f(x)=x6+x2+x7+x12
1 answer:
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The graph Plot of the given results shown represents; A relation only
<h3>How to interpret a scatter plot?</h3>
For it to be a function, then no x-value can produce more than 2 y-values. However, we see that at x = 25, y has 2 values. Similarly, at x = 15, y has two values.
Thus, the graph plot can only be a relation as it is not a function as seen from the points plotted in the graph.
The complete question is;
Mrs. Anderton is giving a test in her third-period class. She has decided to record the amount of time that each student takes to finish the test (in minutes) and compare that to the grade each student receives on the test (out of 100). A plot of her results is below. Which of the following does this situation represent?
A. both a relation and a function
B. a function only
C. neither a relation nor a function
D. a relation only
Read more about Scatter Plot at; brainly.com/question/6592115
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Answer:
they're all like terms so we just add and subtract
Te x intercepts are where the graph crosses the x axis or wher y=0
the y intercept is where the graph crosses the y axis or where x=0
to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a
so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8
vertex is (-2,-8)
intercepts
x intercept is where y=0
0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)
yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)
vertex at (-2,-8)
xints at x=
and 
or at the points 
and 
yint at y=7 or at (7,0)
the y intercept is where the graph crosses the y axis or where x=0
to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a
so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8
vertex is (-2,-8)
intercepts
x intercept is where y=0
0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)
yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)
vertex at (-2,-8)
xints at x=
yint at y=7 or at (7,0)