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2 years ago

7

A group of friends wants to go to the amusement park. They have

1 answer:

Murrr4er [49]2 years ago

8 0

Answer:

Step-by-step explanation: The answer is 6 friends. Assuming that the group is going in one car. Leaving them with 100.5 to spend on admission.You can add the admission fee 6 times until they have nothing left

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Alex originally paid $5200 for her car 1 year ago. The value of her car would is $4,420. What is the percent of decrease in the

horsena [70]

See the picture for the answer.

8 0

3 years ago

What is the surface area of a cube that measures 5 inches on each side?

Kryger [21]

Answer:

150 in²

Step-by-step explanation:

5 x 5 x 6 = 150

surface area of cube is 6 times (6 congruent faces) of one face. 5 x 5 = 25

25 x 6 = 150

5 0

3 years ago

(9, 19) (2, 16)<br> Write the coordinates as decimals or integers.

9966 [12]

Answer:

In decimal 0.428571428

Step-by-step explanation:

The slope = (y2 - y1)/(x2 - x1) y2 = 16, y1 = 19x2=2 and x1=9

The slope = (16 - 19)/(2 -9)

The slope = (-3)/(-7)

The slope = 0.428571428

So in decimal form the coordinates are going to be written as 0.428571428

Slope is the steepness of a line, it is the difference between the y coordinates divided by the difference in x coordinates.

6 0

3 years ago

What is 7/4 times 7/3

yaroslaw [1]

49/12

Just mulitply the top and the bottom across.

7*7/4*3

49/12

7 0

3 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago