Find the perimeter of the square 4x+3 in and 3(2x-5) in

Use the distributive property to expand the expression: 6 (5x-8)

USPshnik [31]

Answer:

30x - 48

Step-by-step explanation:

6 (5x) = 30x

6 (-8) = -48

30x - 48

3 0

3 years ago

Read 2 more answers

Find the missing number:

Makovka662 [10]

Answer:

20%

Step-by-step explanation:

If you see they say that the number decreased is 10% each and they say it two times. we could see that the missing number is as big as the length of two 10% together, so if you add them two you get 20%.

7 0

3 years ago

The cost of a circular table is directly proportional to the square of the radius. A circular table with a radius of 50cm costs

Lana71 [14]

Answer:

£135 is the correct answer.

Step-by-step explanation:

Let C be the cost of table.

And let R be the radius of table.

Cost of table is directly proportional to square of radius.

As per question statement:

$C\propto R^{2}$ or

$C=a\times R^2 ....... (1)$

where $a$ is the constant to remove the $\propto sign$ .

It is given that

$C_1 =$ £60 and $R_1 = 50\ cm$

$C_2 = ?$ when $R_2= 75\ cm$

Putting the values of $C_1$ and $R_1$ in equation (1):

$60=a \times 50^2 ....... (2)$

Putting the values of $C_2$ and $R_2$ in equation (1):

$C_2=a \times 75^2 ....... (3)$

Dividing equation (2) by (3):

$\dfrac{60}{C_2}= \dfrac{a \times 50^2}{a \times 75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{50^2}{75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{2^2}{3^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{4}{9}\\\Rightarrow C_2 = 15 \times 9 \\\Rightarrow C_2 = 135$

So, £135 is the correct answer.

7 0

3 years ago

If f(x) = 3x^5 + 4x^4 + 5, then what is the remainder when f(x) is divided by X + 3?

Musya8 [376]

Answer:

remainder: -400

Explanation:

$\sf f(x) = 3x^5 + 4x^4 + 5$

divided by x + 3

x + 3 = 0

x = -3

insert x = -3 in the function

$\sf f(x) = 3(-3)^5 + 4(-3)^4 + 5$

$\sf f(-3) = -400$

5 0

3 years ago

Find the volume of the solid whose base is the region in the first quadrant bounded by y=x^3, y=1, and the y axis whose cross se

vodomira [7]

The region in question is the set

$R = \left\{ (x, y) : 0 \le x \le 1 \text{ and } x^3 \le y \le 1 \right\}$

or equivalently,

$R = \left\{ (x, y) : 0 \le y \le 1 \text{ and } 0 \le x \le \sqrt[3]{y} \right\}$

Cross sections are taken perpendicular to the y-axis, which means each section has a base length equal to the horizontal distance between the curve y = x³ and the line x = 0 (the y-axis). This horizontal distance is given by

y = x³ ⇒ x = ∛y

so that each triangular cross section has side length ∛y.

The area of an equilateral triangle with side length s is √3/4 s², so each cross section contributes an infinitesimal area of √3/4 ∛(y²).

Then the volume of this solid is

$\displaystyle \frac{\sqrt3}4 \int_0^1 \sqrt[3]{y^2} \, dy = \frac{\sqrt3}4 \int_0^1 y^{2/3} \, dy = \frac{\sqrt3}4\cdot\frac35 y^{5/3} \bigg|_0^1 = \boxed{\frac{3\sqrt3}{20}}$

I've attached some sketches of the solid with 16 and 64 such cross sections to give an idea of what this solid looks like.

3 0

2 years ago