Let C = cost to rent each chair Let T = cost to rent each table
4C + 8T = 73
2C + 3T = 28
Multiply the 2nd equation by (-2) then add the equations together
4C + 8T = 73
-4C - 6T = -56
2T = 17
T = 17/2 = 8.5 Plug this in to the 1st equation to solve for C
4C + 8(17/2) = 73
4C + 68 = 73
4C = 5
C = 5/4 = 1.25
cost to rent each chair is $1.25
cost to rent each table is $8.50
Oh, well that is just weird because the sixth student could be below average, average, or above average so there really is no way to tell. At least not from what I know now.
Answer:
The answer is 8cm.
Step-by-step explanation:
The scale drawing uses a ratio of 2cm:1m. If the actual car is 4 meters long, you would multiply 2 by 4 to get 8cm. The actual new ratio on the map is 8cm:4m, which is equivalent to the one in the problem.
The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:
Differentiate the function with respect to t
Set to 0
So, we have:
Collect like terms
Solve for t
Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
First we count how many hours is inbetween 8 and 3 which is 7
then subtract 10 for the first time
6:50 then add 45 for the second time
7:35
round down so she worked 7 1/2 hours