All categories

2 years ago

Help help help help math

Mathematics

2 answers:

Sholpan [36]2 years ago

6 0

Answer:

Step-by-step explanation:

Sub x=2, y = 1

2(x) + y = 5

2(2) + 1 = 5

lidiya [134]2 years ago

3 0

Answer:

Step-by-step explanation:

2x+y

=2(2)+1

=4+1

You might be interested in

Plz gyz ineed the calculation

sergejj [24]

Answer:

Step-by-step explanation:

so he spends : 1/5 , 1/2 , 1/10.....common denominator of 10

1/5 + 1/2 + 1/10 = 2/10 + 5/10 + 1/10 = 8/10 = 4/5

so he spends 4/5 of his income.

that means he saves : 1 - 4/5 = 5/5 - 4/5 = 1/5 <==

8 0

3 years ago

The measures of the angles of a triangle are ∠A = (2x)°, ∠B = (x+14)°, ∠C = (x−38)° Determine the value of x. Determine A B and

nexus9112 [7]

Answer:

Step-by-step explanation:

Measures of angles are,

m∠A = (2x)°

m∠B = (x + 14)°

m∠C = (x - 38)°

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

2x + (x + 14) + (x - 38) = 180

(2x + x + x) + (14 - 38) = 180

4x - 24 = 180

4x = 204

x = 51

m∠A = 2(51)° = 102°

m∠B = (51 + 14)° = 65°

m∠C = (51 - 38)° = 13°

4 0

3 years ago

Kedar earns a monthly salary of $2,200 plus a 3.75% commision on the amount of his sales at men's clothing store. What would he

Dmitriy789 [7]

Answer:

$2368.75

Step-by-step explanation:

Kedar earns a monthly salary of $2200 and a commission of 3.75%

He sold $4500 this month

The first step is to calculate his commission for this month

His commission can be calculated as follows

= 4500 × 3.75/100

= 4500 × 0.0375

= 168.75

Therefore yr amount earned this month can be calculated as follows

= 2200 + 168.75

= $2368.75

7 0

3 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

3 years ago

Adele opens an account with $120 and deposits $45 a month. Kent opens an account with $80 and also deposits $45 a month. Will th

Alina [70]

No they wont have the same amount because adele will have 50 dollars more each month

3 0

3 years ago