Question

A plane is approaching an aircraft carrier at 25° angle of elevation from 3.2 miles away how far above sea level is the plane

Answer 1

Answer:

$Height\approx 1.35\ miles$

Step-by-step explanation:

The angle of elevation$=25\textdegree$

It is $3.2\ miles$ away from the point.

If we imagine a right  triangle having an angle $25\textdegree$.

Hypotenuse$=3.2$, Opposite=Height from sea level$(h)$

$\sin 25=\frac{opposite}{hypotenuse}\\\\\sin 25=\frac{h}{3.2}\\\\h=3.2\times \sin 25\\\\h=3.2\times 0.4226\\\\h=1.3524\approx 1.35\ miles$

Answer 2

Answer:

1.49

Step-by-step explanation: