The answer is true!
explaination: hope this helped
Answer:
Step-by-step explanation:
1. You can use the intercepts to graph the line. The graph of 2x + 3y = 12 crosses the x-axis at (6, 0), so its x-intercept is 6. The graph of 2x + 3y = 12 crosses the y-axis at (0, 4), so its y-intercept is 4.
2. Point-Slope Form: y - y1 = m(x - x1)
Standard Form: ax + by = c
5x - 2y = 10
-2y = -5x + 10
y = (5/2)x - 5 The slope is 5/2.
y - 2 = (-5/2)(x - 10)
y = (-5/2)x + 25 + 2
y = (-5/2)x + 27 The slope is -5/2.
y = (-5/2)x - 10 The slope is -5/2.
Answer:
c) 58x2
Step-by-step explanation:
Twice the number 29 is 58
So, 29 is related to 58
Therefore 29*4 = 58*2
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
43 < y - 30
add 30 to both sides
73 < y
y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.
Hope this helps!
