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goldfiish [28.3K]
3 years ago
10

A group of neighbors are constructing a community garden that is 80 m wide and 40 m long the top to vertex are plotted below at

10, 70 and 90, 70 what are the coordinates from the bottom to vertex of the garden
Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Question Correction

A group of neighbors are constructing a community garden that is 80 meters wide and 40 meters long. The top two vertices are plotted below at (10, 70) and (90, 70). What are the coordinates for the bottom two vertices of the garden?

Answer:

(10,30) and (90,30)

Step-by-step explanation:

The community garden is 80 m wide and 40 m long.

The top two vertex are plotted at: (10, 70) and (90, 70).

Horizontal Distance =90-10=80

This serves as the Width of the garden.

Since the length is 40m, the bottom two vertex can be derived by the transformation: (x,y-40).

(x,y-40)-->(10, 70)=(10,30); and

(x,y-40)-->(90, 70)=(90,30)

The coordinates for the two bottom vertices are (10,30) and (90,30).

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Explanation

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,

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In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

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3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

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Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

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1 year ago
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It can then be concluded that each parent ate \frac{1}{12} of the cake, since there was \frac{2}{12} remaining. 

You can check this answer by adding up all of the parts we used in this problem:

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