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storchak [24]
3 years ago
10

The diagram shows several planes, lines, and points. Which statement is true about line h? Line h intersects line f at two point

s, A and B. Line h is the intersection of planes R and T. Line h intersects plane P at point C. Line h has points on planes R, P, and T.
Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Did the test

Dafna11 [192]3 years ago
4 0

Answer:

According with the diagram and using the definitions of planes, lines, and points, the statement true about line h is:

d. Line h has points on planes R, P, and T.

Solution:

a. Line h intersects line f at point B, the the statement a. is false.

b. Line h is on plane R, but is not in the intersection of two planes. Line g is in the intersection of planes R and T,, then statement b. is false.

c. Line l intersects plane P at point C, then statement c. is false.

d. Line h has points on planes R, P, and T, then statement d. is true.

Step-by-step explanation:

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A line passes through the points (2,13) and (9,20). Write a linear function rule in terms of x and y for this line. The linear f
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Step-by-step explanation:

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3 0
3 years ago
Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2
lbvjy [14]
Step 1:
Start by putting \frac{d}{dx} in front of each term

\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}

y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make \frac{dy}{dx} the subject
-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
cos(x)  \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)
[cos(x) - 6y]  \frac{dy}{dx}=10x + y sin(y)
\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y} ⇒ Final Answer


5 0
4 years ago
23792743598437589643252963405 x 23792743598437589643252963405
dezoksy [38]

5.6609465e+56

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