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insens350 [35]
3 years ago
9

For the given​ data, (a) find the test​ statistic, (b) find the standardized test​ statistic, (c) determine the​ p-value, and​ (

d) decide whether you should reject or fail to reject the null hypothesis. the samples are random and independent. ​claim: mu 1μ1less than
Mathematics
1 answer:
Feliz [49]3 years ago
6 0
<span>You should reject or fail to reject the null hypothesis. the samples are random and independent. ​claim: mu 1μ1less than 50.</span>
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Use the rectangle below to answer both parts of the question.
trasher [3.6K]

Answer:

part 1= "72=(2w)+(w-15)"

part 2= "29"

I'm not sure if they want "w = abc"

I used that equation to solve part 2

Hope this helps you, I've been where you are

6 0
3 years ago
Will give brainliest
Dovator [93]

Answer:

GURL MY MATH TEACHER GAVE ME THE SAME SHEET A MONTH AGOO

YASS

1.) x is less than or equal to 3

2.) x greater than or equal to 2

3.) x < -1

4.)  x greater than or equal to 3

5.) x>2

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5 0
3 years ago
HD Straight line graphs
Taya2010 [7]

Answer:

The equation of the sraight line  3x- y+ 6 =0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the gradient of the function

   |gradf| = 3  and point (-1,3)

Given that the slope of the line

 m = 3

The equation of the straight line passing through the point(-1,3) and slope m =3

y -y_{1} = m(x-x_{1} )

y-3 = 3(x-(-1))

y-3 = 3x+3

3x +3-y+3=0

3x- y+ 6 =0

<u><em>Final answer:-</em></u>

The equation of the sraight line  3x- y+ 6 =0

<u><em></em></u>

   

5 0
3 years ago
(10, -17), (-10, -14)
Alexus [3.1K]

Answer:

3/-20

Step-by-step explanation:

I think you were asking for the slope for these, so that's what I gave you, sorry if you needed something else

5 0
3 years ago
This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0
3 years ago
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