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3 years ago

Use the rectangle below to answer both parts of the question.

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

Answer:

part 1= "72=(2w)+(w-15)"

part 2= "29"

I'm not sure if they want "w = abc"

I used that equation to solve part 2

Hope this helps you, I've been where you are

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Help with this tape diagram

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3 years ago

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On his math test, Balavan wrote that a four-sided polygon that has at least two right angles must be a rectangle or a square. De

gregori [183]

A quadrilateral with only 2 right angles could be a trapezoid so Balavan is wrong. Denna is right because if 3 angles are right angles the the fourth angle must also be a right angle and has to be a square or rectangle.

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3 years ago

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Law of cosines: a2 = b2 + c2 – 2bccos(A) What is the value of n to the nearest whole number? 18 22 29 41

nalin [4]

We know that
applying the law of cosines
a² = b²+ c²<span> – 2*b*c*cos(A)
</span>
in this problem
a=?
b=20
c=9
A=90°
so
a² = b²+ c² – 2*b*c*cos(A)
but
cos (A)=0
a² = b²+ c²-----> 20²+9²----> a²=400+81----> a²=481-----> a=√481
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the answer is
22

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4 years ago

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Consider the line y=9x-1.

OLEGan [10]

Step-by-step explanation:

Slope=9

$y−y1=m(x−x1)$

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y+5=9(x-6)

y+5 = 9x - 54

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y+5=-1/9(x-6)

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<h2>MARK ME AS BRAINLIST </h2>

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$