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3 years ago

(10, -17), (-10, -14)

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

Answer:

3/-20

Step-by-step explanation:

I think you were asking for the slope for these, so that's what I gave you, sorry if you needed something else

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1933-36<br> 1937-40<br> 1931-33<br> 1931-34

sdas [7]

I don't really know

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2 years ago

What are the zeros of the function f(x) = x4 − 4x2 − 5?

Gekata [30.6K]

Answer:

A graph shows zeros to be ±3. Factoring those out leaves the quadratic

(x-2)² +1

which has complex roots 2±i.

The function has roots -3, 3, 2-i, 2+i.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which of the following is the product for (x+4)(x-2)?

larisa86 [58]

Answer:

Step-by-step explanation:

X times x is x squared then x times - 2 is - 2x but 4 times x is 4x. So 4x plus - 2x is 2x. Then 4 times - 2 is - 8 put that all together you'll get x^+ 2+2x-8

6 0

3 years ago

Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe

Rama09 [41]

You can see how this works by thinking through what's going on.

In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97

What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

So the population after x years is 1200 * 0.97x

5 0

3 years ago

You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend

Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

4 0

2 years ago