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3 years ago

Solve the equation for x, where x is a real number (5 points): -11x^2 + 5x - 3 = 0

1 answer:

7 0

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
                   x = [-5 ± √(25 - (132) ) ] / ( -22 )
                   x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.

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Answer:#4 is 3L Starwberry juice and 6L orange Jucie.

Step-by-step explanation:

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2 years ago

Write a mixed number for P so that 3 and 1/4 time P is more than 3 and 1/4

mafiozo [28]

Just pick a number greater than 1 and that would be for P

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3 years ago

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I need help, Paul drew a net for a square pyramid. Which figure could be the one Paul drew?

Ronch [10]

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2 years ago

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What’s the volume of 1.) V=txrxrxh = 3.14 X 3 X 3 X 4 5 cm 12 cm

KonstantinChe [14]

9514 1404 393

Answer:

A) (3 cm x 4 cm ÷ 2) x 3 cm

Step-by-step explanation:

The volume is the product of the area of the triangular bases and the distance between them.

Each right triangular base has a width of 3 cm and a height of 4 cm. Its area will be given by ...

A = (1/2)bh

A = (1/2)(3 cm)(4 cm) = (3 cm × 4 cm) ÷ 2

The distance between the triangular bases is marked at the left side of the diagram as 3 cm. So, the volume is ...

V = Bh

V = (3 cm × 4 cm ÷ 2) × 3 cm . . . . . matches choice A

There aren't any more steps. The answer starts by saying how the volume is computed. Then it shows how to find the numbers that go into that computation. Finally, it puts all that together in the form that is required to match an answer choice.

It might also be useful for you to draw the net to scale on a piece of paper, cut it out, and fold it along the lines to actually make a triangular prism. A little hands-on is always helpful in math. It only takes 5 or 10 minutes and can give you great insight into both prisms and nets.

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2 years ago

If mc021-1.jpg and mc021-2.jpg, what is the range of mc021-3.jpg?

sergeinik [125]

$u(x)=-2x^2+3$ , and $v(x)= \frac{1}{x}$ ,

we want to find the range of $(u\circ v)(x)=u(v(x))$

Notice that Whatever value v can possibly produce, that is the Range of v, becomes the range of u.

Then whatever u produces for these values, is the range of u(v(x))

So, first find range of v: clearly the domain of v is R-{0}, as v(0) makes no sense.

We check what values c can v produce:

$\frac{1}{x}=c\\\\x= \frac{1}{c}$ ,

this means that any c (for now) can be produced... it is enough to let x=1/c

this also means that c cannot be equal to 0 as 1/c makes no sense if c=0.

Thus the range of v is R-{0},

Now we check the range of u(v(x)) for v(x)∈R-{0},

assume we want to produce a value c, so:

$c=-2x^2+3\\\\-2x^2=c-3\\\\x^2= \frac{c-3}{-2}$

since the left side is always positive or 0, for x=0, the right hand side expression must also be positive or zero, which means c-3 must be negative or 0,

thus c-3≤0; c≤3. Here recall that x in u(x) cannot be 0, so c<3.

Answer: The range of u(v(x)) is (-infinity, 3)

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3 years ago