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Hunter-Best [27]

3 years ago

9

Solve the equation for x, where x is a real number (5 points): -11x^2 + 5x - 3 = 0

1 answer:

fenix001 [56]3 years ago

7 0

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
                   x = [-5 ± √(25 - (132) ) ] / ( -22 )
                   x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.

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Determine whether each quadrilateral is a parallelogram. Justify your answer. Yes/No? Reason... opposite side congruent, opposit

Alex_Xolod [135]

Answer:

Yes! The given quadrilateral represents Parallelogram.

Reason: The given quadrilateral has opposite sides congruent.

Step-by-step explanation:

Given the quadrilateral with the four vertices.

Now in order to determine whether the given quadrilateral is a parallelogram or not, we need to check whether the opposite sides are congruent or not.

It is clear that the given quadrilateral has opposite sides congruent.

Therefore, the given quadrilateral represents Parallelogram.

Hence,

Yes! The given quadrilateral represents Parallelogram.

Reason: The given quadrilateral has opposite sides congruent.

7 0

3 years ago

Need help on #7 help if u know how to solve thanks!

mash [69]

7a) 302.5
7b) 302500
Hope this helps! :)

8 0

3 years ago

Read 2 more answers

5 times marys age is the same as 28 less than 7 times her age. Find her age

Gnom [1K]

setup a simple algebraic equation and solve.

5x = 7x-28

-5x -5x

0=2x-28

+28 +28

28=2x

Now divide both sides by 2 and you get that she is 14

3 0

3 years ago

Read 2 more answers

Can someone please help me with this ?

Galina-37 [17]

Answer:

Step-by-step explanation:

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3 0

3 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

7 0

3 years ago