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Hunter-Best [27]
3 years ago
9

Solve the equation for x, where x is a real number (5 points): -11x^2 + 5x - 3 = 0

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
                   x = [-5 ± √(25 - (132) ) ] / ( -22 )
                   x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.
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Topic: Absolute Value Equations and Inequalities
jolli1 [7]

The values of  x are -22 and -2 and there are not extraneous solutions

<h3>How to solve the equation?</h3>

The equation is given as:

2|x + 7|= x - 8

Expand the absolute bracket

|2x + 14|= x - 8

Remove the absolute bracket

2x + 14 = x - 8 and 2x + 14 = -x + 8

Evaluate the like terms

x = -22 and 3x = -6

This gives

x = -22 and x = -2

Hence, the values of  x are -22 and -2 and there are not extraneous solutions

Read more about absolute value expressions at:

brainly.com/question/24368848

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