Solve the equation for x, where x is a real number (5 points): -11x^2 + 5x - 3 = 0

1 answer:

7 0

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
                   x = [-5 ± √(25 - (132) ) ] / ( -22 )
                   x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.

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7. Over the past 50 years, the number of hurricanes that have been reported are as follows: 9 times there were 6 hurricanes, 13

poizon [28]

Answer:

Step-by-step explanation:

Let us first generate the frequency table from the information given:

Hurricane number(X) Frequency(f) f(X)

6 9 54

8 13 104

12 16 192

14 12 168

Total ∑(f) = 50 ∑f(x) =518

In order to determine the last frequency (the remaining years), we will add the other frequencies and subtract the answer from 50, which is the total frequency (50 years). This is done as follows:

Let the last frequency be f

9 + 3 + 16 + f = 50

38 + f = 50

f = 50 - 38 = 12

Now, calculating mean:

$\bar {X} = \frac{\sum f(x)}{\sum(f)} \\\\\bar {X} = \frac{518}{50} \\\\\bar {X} = 10.36$

Therefore mean number of hurricanes = 10.4 (to one decimal place)

7 0

2 years ago

In a book the characters are trying to determine whether the Poisson probabilistic model can be used to describe the locations t

oksian1 [2.3K]

Answer:

The estimated mean number of rockets hits in the region is 533.

Step-by-step explanation:

We are given the following information,

Number of rocket hits | Observed number of regions

0 | 228

1 | 214

2 | 94

3 | 32

4 | 7

5 | 0

6 | 0

7 | 1

We are asked to estimate the mean number of rocket hits in the region.

The mean or expected value is given by

$\mu = \sum (x \cdot P(x)) \\\\\mu = (0 \cdot 228) + (1 \cdot 214) + (2 \cdot 94) + (3 \cdot 32) + (4 \cdot 7) + (5 \cdot 0) + (6 \cdot 0) + (7 \cdot 1) \\\\\mu = 0 + 214 +188+ 96 +28 +0+ 0 + 7 \\\\\mu = 533$