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3 years ago

3x - 8 < -2x +22 solve the inequality

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

5 0

kotegsom [21]3 years ago

4 0

X < 6
Hope it helped!

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Are there always the same number of prime numbers between 2 consecutive multiples of 10? Why?

galina1969 [7]

Answer:

Yes it is 5

Step-by-step explanation:

It is 5 because you divide 2 and 10 and it is 5

4 0

3 years ago

I need help please and thank you

Stels [109]

Answer:

2.72 x 10^4

Step-by-step explanation:

2.4 x 10^4

= 24000

3.2 x 10^3

= 3200

Therefore,

(2.4 x 10^4) + (3.2 x 10^3)

= 24000 + 3200

= 27200

= 2.72 x 10^4

8 0

3 years ago

5(g+8)-7=103<br>what's the answer?

castortr0y [4]

Do you need the steps? g=14

3 0

3 years ago

Read 2 more answers

200 divided by 5.50 is what because if one hour is 5.50 and you need 200 how many hours do you work

Phoenix [80]

Answer:

if you divided 200 by 5.50 the answer will be 36.3636363636

8 0

2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago