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ASHA 777 [7]
3 years ago
5

Find the length of the line segment that connects the points (7, 16) and (47, 140)​

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

length =  \sqrt{ {(47 - 7)}^{2}  +  {(140 - 16)}^{2} }  \\  =  \sqrt{ {40}^{2}  +  {124}^{2} }  \\  =  \sqrt{16976}  \\  = 130.29 \: units

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Answer is 68$

Step-by-step explanation:

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3 years ago
Which matrix is singular? <br><br>A. A <br><br>B. B <br><br>C. C <br><br>D. D
anyanavicka [17]

Answer:

D. \left[\begin{array}{ccc}-12&-4\\9&3\end{array}\right]

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3 years ago
Write 5 to the power of 3 x √5 as a single power of 5
Lesechka [4]

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Step-by-step explanation:

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3 years ago
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What is 8 plus 9 subtract 7 divided by 1,000
Olin [163]
| The answer is 0.01 | 
8 0
3 years ago
How can I get the area of the shaded region?
almond37 [142]

Let's work on the triangle first.  The x intercept of 2y=27-3x is

0 = 27 - 3x

3x = 27

x = 9

So A(9,0)

B is the meet of 2y=27-3x and y=3x

2y=27-y

3y=27

y=9

y is the height of OAB; we don't really need x

Area(OAB) = \frac 1 2 (9)(9) = \frac{81}{2} = 40.5

Now we have to subtract

\displaystyle \int_0^9 (3x - x^{\frac 3 2})dx = \frac 3 2 x^2 - \frac 2 5 x^{\frac 5 2} \bigg|_0^9 = \frac 3 2 (9^2) - \frac 2 5 (9^{\frac 5 2}) = \frac{1}{2}(243) - \frac 2 5 (243) = 24.3

Area = 40.5 - 24.3 = 16.2

Answer: 16.2


4 0
3 years ago
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