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Y_Kistochka [10]
3 years ago
10

What is the end behavior of the function f(x) = -3x4-x3 + 2x2 + 4x + 5?

Mathematics
2 answers:
sp2606 [1]3 years ago
6 0

Answer:

down on left, down on left

Step-by-step explanation:

<em>Look at the first term or the one with the highest degree.</em>

Even Degree and positive coefficient: <em>*</em>up left* and *up right*

Even degree and negative coefficient: *down left* and *down right*

Odd Degree and positive coefficient: *down left* and *up right*

Odd Degree and negative coefficient: *up left* and *down right*

Mariulka [41]3 years ago
3 0
The domain of the function is  - infinity to -+ infinity (R), the terminal limits are unique, it is - infinity
so the answer is down on the left, down on the right
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Fudgin [204]

Answer:

(x+4)^2+(y+6)^2=100

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

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To find its equation, we follow these steps.

Step 1: Determine its radius, r using the distance formula

For point P(-4,-6) and R(2,2)

\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

Step 2: Determine the equation

The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: (x-h)^2+(y-k)^2=r^2

Centre,(h,k)=P(-4,-6)

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Therefore, the equation of the circle is:

(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

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3 years ago
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