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Gre4nikov [31]
3 years ago
15

A certain drug concentration of 2.145 mg per 1.716 mL, how many mL are needed to give 2.937 gram of the drug.

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0

Answer:

2,349.6‬ ml

Step-by-step explanation:

To start solving this, i realized that there was a difference in the units given and the units asked for in the answer, so I converted 2.937 grams to 2,397 mg. It is given that there are 2.145 mg of the drug in 1.716 mL, so set up the equation 2.145 / 1.716 = 2,937 / x, where x is the mL of the drug needed. Cross multiply to get 5039.892 = 2.145 x. Divide by 2.145 and get 2,349.6‬ ml

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3 years ago
What is the difference between the 208.472 and 149.361
Artemon [7]
The answer would be 59.111
5 0
3 years ago
Find the circumference of the figure.
shtirl [24]

Answer:

About 23.9 in

Step-by-step explanation:

We are given ;

a circle whose radius is 3.8 inches

we are required to determine the circumference

The circumference is given by the formula;

=2πr

Therefore;

Circumference = 2×3.14×3.8 in

                       =23.864 in

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4 0
3 years ago
A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi
Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is \mu \times n and the standard deviation is \sigma\sqrt{n}

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that \mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 20000}{300}

Z = 0

Z = 0 has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0
3 years ago
PLEASE HELP NOW NOW NOW PLEASE PLEASE HELP
bija089 [108]

Answer:

$46.00

Step-by-step explanation:

$46.00 - $20 + $5 = $21

7 0
3 years ago
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