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N76 [4]
3 years ago
5

Subtract 3x^2+7x-4 from 8x^2-6x+2

Mathematics
1 answer:
solong [7]3 years ago
3 0

Answer:

5x^2-13x+6

Step-by-step explanation:

(8x^2-6x+2)-(3x^2+7x-4)

8x^2-3x^2-6x-7x+2-(-4)

5x^2-13x+2+4

5x^2-13x+6

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What is the difference of 11 and 3.5?​
Deffense [45]
7.5

Explanation:
11-3.5=
Take 3 away form 11 and then get 8 then subtract.5 and you are left with 7.5
6 0
3 years ago
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Ella is a landscape photographer. One weekend at her gallery she sells a total of 52 prints for a total of $2,975. A small paint
rosijanka [135]
<h2>Answer:37 paintings of $50 and 15 paintings of $75</h2>

Step-by-step explanation:

Let x be the number of paintings Ella sells for $50.

Let y be the number of paintings Ella sells for $75.

Profit made through $50 paintings is 50x

Profit made through $75 paintings is 75y

So,total profit is given by 50x+75y

It is given that total profit is $2975

So,50x+75y=2975      ..(i)

Given that the total number of prints is 52

So,x+y=52      ..(ii)

using (i) and (ii),

50x+75(52-x)=2975\\50x+3900-75x=2975\\25x=925\\x=37

y=52-x=52-37=15

7 0
4 years ago
Read 2 more answers
Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and
jenyasd209 [6]

Equation of a line is x+3y =-3.

<h3>What is a perpendicular bisector of the line segment?</h3>

A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.

Given that,

Endpoints of the line segment are (x_{1},y_{1}) = (4, 1) and (x_{2},y_{2}) = (2, -5).

First find the midpoints of the given line segment.

M = \left(\frac{x_{1}+x_{2}  }{2},\frac{y_{1}+y_{2}  }{2}\Right)

    =  \left(\frac{4+2  }{2},\frac{1-5  }{2}\Right)

M   =  (3,-2)

Now, Find the slope of the line :

It is perpendicular to the line with (4,1) and (2,-5)

Slope between (x_{1},y_{1}) and (x_{2},y_{2}) = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

so,

the slope between (4,1) and (2,-5)  =  \frac{-5-1  }{2-4 }

                                                         = 3

perpendicular lines have slopes the multiply to get -1

3 times m=-1

m= \frac{-1}{3}

The equation of a line that has a slope of m and passes through the midpoints M(3,-2)  is

y-y_{1} =m(x-x_{1} )

y-(-2) =\frac{-1}{3} (x-3 )

(y+2) =\frac{-1}{3} (x-3 )

if we want slope intercept form

(y+2) =\frac{-1}{3} x+1

y= \frac{-1}{3} x-1

If we want standard form

\frac{1}{3} x+y = -1

x+3y =-3

Hence, Equation of a line is x+3y =-3.

To learn more about perpendicular bisector of the line segment from the given link:

brainly.com/question/4428422

#SPJ4

   

7 0
1 year ago
The quotient of two times a number k and -2.6 is 12
a_sh-v [17]
-15.6 Is the answer. You do inverse
7 0
4 years ago
find two consecutive odd intergers that twice the larger is fifteen more than three times the smaller
Svetach [21]

Answer:

11, 13

Step-by-step explanation:

an odd number can be represented by 2n+1

since they are consecutive, the larger odd number will be 2n + 1 + 2

now,

2(2n+3) = 2n + 1 +15

solving this eqn, we get n = 5

so the two numbers are (2n+1) = 11 and 11+2= 13

4 0
3 years ago
Read 2 more answers
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