The exponent is the 3 over the x
Answer:
The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
Step-by-step explanation:
We are given 
We need to solve for x
First we subtract 2 both sides

Taking cube roots both sides to isolate x
![x=\sqrt[3]{16}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B16%7D)
Simplify the radical
![x=2\sqrt[3]{2}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B2%7D)
Thus, The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
The easy way to think about this is what number comes between 5 and 7? The answer is 6 (but we have to consider that it's negative in this case.) So the answer is -6 Another way to look at it is with a number line (not to "Which number is greater than -7 and less than -5"? scale.)<===(-7)==(-6)==(-5)==(-3)==(-2)==(-1)==(0)==(1)==>Notice how -6 comes between the two numbers. -6 is larger than -7 (it's "less negative" -- "Which number is greater than -7 and less than -5"? closer to zero) -6 is less than -5 (it's "more negative" -- further away from zero)
Answer:
8
Step-by-step explanation:
Just flip it up... it will be 8