Hello,
1: 9n-3=21 ==>B
2: 3n+9=21 ==>A
3: 9n-3=21 ==>B
4: 3n-9=21 ==>C
I wish to have understood all those sentences.
The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
Find out more information about theoretical probability here:
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The proportion would be the number of the sample (x) over the population size (n)
Here we have x = 59,969 and n= 461,299
P = x/n = 59969/461299
P = 0.13
Answer:
80/1 1/4 (Fraction)
Step-by-step explanation:
