Question has missing details (Full question below)
Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage
Answer:
Mean = 219
Variance = 4
Step-by-step explanation:
Given
Let X be a random variable measurement error.
X has a discrete uniform distribution as follows
a = 219 - 3 = 216
b = 219 + 3 = 222
Mean or Expected value is calculated as follows;
E(x) = ½(216+222)
E(x) = ½ * 438
E(x) = 219
Variance is calculated as follows;
Var(x) = ((b-a+1)²-1)/12
Var(x) = ((222-216+1)²-1)/12
Var(x) = (7²-1)/12
Var(x) = 48/12
Var(x) = 4
Answer:
8
Step-by-step explanation:
The domain is from the points (-4,0) through (4,0).
Answer:
Joey has 18 nickles and 27 dimes in his piggy bank.
Step-by-step explanation:
1 nickle = 5 cents
1 dime = 10 cents
$1 = 100 cents
$3.15 = 135 cents
Let
n represent the number of nickles, n>=0
d represent the number of dimes, d>=0
Joey counted a total of 45 coins that added up to $3.15:
n + d = 45
5n + 10d = 315
n = 18 nickles
d = 27 dimes
#1,4 are biased because the number range is too wide. (include #2 if the question allows)
#1: 31-20 = 11
#2: 29-21 = 8
#3: 30-23 = 7
#4: 50-15 = 35 (OMG that's so biased!)
so if the three surveys are eliminated, then the answer to the second question is 23%.
Hope that helps :)
