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Oduvanchick [21]
4 years ago
5

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4

+ NH3 + O2  HCN + H2O You have 10 g of methane and 12 g of ammonia in excess oxygen. Answer the following questions: What is the balanced equation for this reaction? Which reagent is limiting? Explain why. How many grams of hydrogen cyanide will be formed? Show your work.
Chemistry
1 answer:
Nataly [62]4 years ago
8 0
2CH4 + 2NH3 + 3O2 ---> 2HCN + 6H2O


10g CH4 x 1molCH4/16.042gCH4 x 2mol HCN/2molCH4 = 0.6mol HCN

12g NH3 x 1molNH3/17.034gNH3 x 2molHCN/2molNH3 = 0.7mol HCN

Methane is the limiting reactant


Use the moles of Hydrogen Cyanide that you would get when used the limiting reactant, Methane

0.6molHCN x 27.028gHCN/1molHCN = 16.2grams --> 16 grams Methane


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