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3 years ago

Give the main conclusion from the 1911

Chemistry

1 answer:

Monica [59]3 years ago

3 0

Answer:

Here's what I get

Explanation:

From the scattering experiments, Rutherford concluded that the positive charge was concentrated in the nucleus of the atom.

This contradicted the plum pudding model, which assumed that the positive charge was uniformly distributed throughout the atom.

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A nitrogen atom and an oxygen atom combine chemically to form nitric oxide. what is nitric oxide?

ExtremeBDS [4]

Nitric oxide is a colorless gas with the formula NO. It is one of the principal oxides of nitrogen. Nitric oxide is a free radical, i.e., it has an unpaired electron, which is sometimes denoted by a dot in its chemical formula

5 0

4 years ago

Give the electronic configuration of carbon atom.

zimovet [89]

Answer:

1s2 2s2 2p2

Explanation:

it has 6 electrons in two energy levels so the sub levels are 1s, 2s and 2p

4 0

3 years ago

Please answer these!!!

olasank [31]

Answer:

1.b. 2.5 mol

2.c.82.8%

3.d. synthesis

4.c . 2:2

5.d. 5 moles

6.c.5.02

7.d.3:1

8.d.2.68 moles

Explanation:

$2RbNO_{3}\rightarrow 2RbNO_{2}+1O_{2}$

Here , 2 mole of RbNO3 will produce, 1 mole of O2

1 mole of RbNO3 will produce =

$\frac{1}{2}$ mole of O2

5 mole of RbNO3 will produce =

$\frac{1}{2}\times 5$

= 2.5 mole of O2

2 .

Molar mass of HCl = 1 + 35.45 = 36.45 gram

Molar mass of CO2 = 12 +32 = 44 gram

1 mole of the substance = molar mass

So , 1 mole of HCl = 36.45 gram

2 mole of HCl = 2 x 36.45 =72.9 gram

1 mole of CO2 = 44 gram

The given equation is :

$CaCO_{3}+2HCl\rightarrow CO_{2}+H_{2}O$

Here CaCO3 is the excess reagent and HCl is the limiting reagent

2 mole of HCl will produce = 1 mole of CO2

72.9 gram of HCl= 44 gram of CO2

so, 1 gram of HCl =

$\frac{44}{72.9}$ gram of CO2

Here we need to calculate the mass of CO2 in 200 gram of HCl.

So, 200 gram of HCl =

$\frac{44}{72.9}\times 200$ gram CO2

=120.71 gram CO2

this is the theoritical yield of CO2 = 120.71 gram

Experimental yield = 100 gram (given)

The percent yield is calculated by:

$=\frac{Experimental}{Theoritical}\times 100$

$=\frac{100}{120.71}100$

= 82.84%

3.Synthesis Reaction : Those reactions in which two or more substances combine to give a single product.

Here NH3 and HCl are combined and giving only one product = NH4Cl

$2H_{2}+1O_{2}\rightarrow 2H_{2}O$

Hydrogen = H2

Water = H2O

Here Ratio of H2 to H2O is 2:2

5.The balanced equation is :

$1Ca(OH)_{2}+2HCl\rightarrow 1CaCl_{2}+2H_{2}O$

The number of atoms on left side should be equal to the right side:

Ca = 1

H = 4

O = 2

Cl = 2

Here, 2 moles of water(H2O) = 2 moles of HCl

So, 5 moles of water will give = 5 moles of HCl

$2Ag(NO)_{3}+BaCl_{2}\rightarrow 2AgCl_{2}+BaNO_{3}$

Molar mass of AgNO3 = 169.87 g/mol

1 mol of AgNO3 = 169.87 gram

Molar mass of AgCl = 143.32 g/mol

1 mole of AgCl = 143.32 grams

According to the given equation ,

2 mole of AgNO3 will give = 2 mole of AgCl

1 mole of AgNO3 = 1 mole of AgCl

169.87 gram of AgNO3 = 143.32 gram of AgCL

1 gram of AgNO3 =

$\frac{143.32}{169.87}$

5.95 gram of AgNO3 =

$\frac{143.32}{169.87}\times 5.95$

= 5.02 grams

7. The mole ratio of Hydrogen (H2) to Nitrogen (N2):

$N_{2}+3H_{2}\rightarrow 2NH_{3}$

H2 = 3 mole

N2 = 1 mole

[H2]:[N2] = 3:1

8. The moles in a substance can be calculated by using :

$moles=\frac{Mass}{Molar\ mass}$

Mass of N2 = 75 grams (Given)

Molar mass = 28 gram

$moles=\frac{75}{28}$

Moles = 2.678 moles

8 0

3 years ago

Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?

BaLLatris [955]

1. The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:

H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]

8 0

3 years ago

The specific heat of copper is 0.4 J/g^ *C If a sample of copper absorbs 480J of energy and its temperature changes from 20.0 ^*

Tanzania [10]

Answer:

The mass of copper that was heated is 30 g

Explanation:

The formula for the heat supplied, ΔH is;

ΔH = m·c·Δt

Where:

ΔH = Heat supplied = 480 J

m = Mass of the copper sample = Required

c = Specific heat capacity of copper = 0.4 J/(g·°C)

Δt = Change in temperature = T₂ - T₁ = 60° - 20° = 40°C

T₁ = Initial temperature = 20°C

T₂ = Final temperature = 60°C

Therefore, plugging the values, we have;

480 = m×0.4×40

m = 480/(0.4 × 40) = 30 g

The mass of copper that was heated = 30 g.

6 0

3 years ago