The approximate volume of the model will be
![v=452.33 inch^{2}](https://tex.z-dn.net/?f=v%3D452.33%20inch%5E%7B2%7D)
<h3 /><h3>What is the approximate volume of the model? </h3>
It is given that
![Height of the volcano =12 inch](https://tex.z-dn.net/?f=Height%20of%20the%20volcano%20%3D12%20inch)
![Diameter of the volcano= 12inch=r=6inch](https://tex.z-dn.net/?f=Diameter%20of%20the%20volcano%3D%2012inch%3Dr%3D6inch)
So the volume of the model will be =
![=\dfrac{1}{3\\} \pi \times r^{2} \times h](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B3%5C%5C%7D%20%5Cpi%20%5Ctimes%20r%5E%7B2%7D%20%5Ctimes%20h)
![= \dfrac{1}{3} \pi \times (6)^{2} \times 12](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20%5Ctimes%20%286%29%5E%7B2%7D%20%5Ctimes%2012)
![v=452.33inch^{2}](https://tex.z-dn.net/?f=v%3D452.33inch%5E%7B2%7D)
Thus the approximate volume of the model will be ![v=452.33 inch^{2}](https://tex.z-dn.net/?f=v%3D452.33%20inch%5E%7B2%7D)
To know more about the volume of the cone follow
https://brainly.in/question/18480521
Answer:
Step-by-step explanation:
v=Q-P
v=(5,1,0)
u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)
u=(5/5.09,1/5.09,0)
v=Q-P
v=(1,1,0)
u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)
u=(1/
,1/
,0)
2(3w-2+w)
=2(4w-2)
=8w-4
the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is <span>2(3w-2+w), and then you just have to simplify that </span>
The question is asking for you to plug in each number in the brackets into x and solve for y, or f(x), g(x), etc. I will do no. 19 as an example:
f(x) = -3x + 1
This problem has the domains -2, -1, and 0. First, we'll start with -2:
f(x) = -3(-2) + 1
f(x) = 6 + 1
f(x) = 7
Now -1:
f(x) = -3(-1) + 1
f(x) = 3 + 1
f(x) = 4
Lastly, 0:
f(x) = -3(0) + 1
f(x) = 0 + 1
f(x) = 1
For question 23, we can use the distance formula, which is ratextime. The domain in this case is time (t). You can set up a function like this: d(t) = 60t