Answer:
y = -(5/2)x -2
Explanation:
The general formula for a straight line is y – mx + b.
The image below shows the graph of the line.
Step 1. <em>Calculate the slope</em>.
Slope = m = Δy/Δx = (y₂-y₁)/(x₂-x₁)
x₁ = 0; y₁ = -2
x₂ = -2; y₂ = 3 Calculate m
m = [3-(-2)]/(-2-0)
m = (3+2)/(-2)
m = 5/(-2)
m = -5/2
Step 2. <em>Calculate the y-intercept
</em>
When x = 0, y = 2.
The y-intercept (b) is at y = -2
Step 3. <em>Write the equation </em>for the graph
y = mx + b
y = -(5/2)x - 2
Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
The graphs that display the same data are a. I and II
<h3>What is Data Representation?</h3>
This refers to the different ways in which a set of data are displayed in a certain place such as a bar graph, frequency table, line graph, etc.
Hence, we can see that from the evaluation of the data, there is the use of the same data in I and II as the bar and line graphs contain the same country voter turnout.
Read more about bar graphs here:
brainly.com/question/25718527
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<span>a. n/4 ≤ -1
Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.
That in the real number line is all the numbers to the left of - 4 (including -4)
The matching graph is the B.
b. -10n ≥ -100
Divide both sides by - 10 => n ≤ 10
That is all the real numbers less or equal than 10.
In the real number line it is all the numbers to the left of 10, including 10.
So, the matching graph is the A.
c. 5x ≥ 20
Divide both sides by 5 => x ≥ 4
That is all the real numbers greater or equal to 4.
In the real number line it is all the numbers to the right of 4, including 4.
The matching graph is C.</span>
