A watt is a unit of power, which measures energy used per unit time. A kilowatt hour means 1 kilowatt of electricity used contin
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Answer:
b) The width of the confidence interval becomes narrower when the sample mean increases.
Step-by-step explanation:
The confidence interval can be calculated as:
a) The width of the confidence interval becomes wider as the confidence level increases.
The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.
b) The width of the confidence interval becomes narrower when the sample mean increases.
The above statement is false. As the sample mean increases the width of the confidence interval increases.
c) The width of the confidence interval becomes narrower when the sample size n increases.
The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.
1. Ans:(A) 123
Given function:
The derivative would be:
=>
=>
=>
Now at x = 7:
=>
2. Ans:(B) 3
Given function:
The derivative would be:
=>
=>
=>
Now at x = 4:
(as constant)
=>Ans:
3
3. Ans:(D) -5
Given function:
The derivative would be:
or
=>
=>
Now at x = -1:
=>
=> Ans:
4. Ans:(C) 7 divided by 9
Given function:
The derivative would be:
or
=>
=>
Now at x = -3:
=>
=> Ans:
5. Ans:(C) -8
Given function:
Now if we apply limit:
=>
=> Ans:
6. Ans:(C) 9
Given function:
Now if we apply limit:
=>
=> Ans:
7. Ans:(D) doesn't exist.
Given function:
In this case, even if we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.
Check:
If you apply the limit, answer would be infinity.
8. Ans:(A) Doesn't Exist.
Given function:
Same as Question 7
If we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.
9, 10.
Please attach the graphs. I shall amend the answer. :)
11. Ans:(A) Doesn't exist.
First We need to find out:
where,
If both sides are equal on applying limit then limit does exist.
Let check:
If x
9: answer would be 9+9 = 18
If x
9: answer would be 9-9 = 0
Since both are not equal, as
, hence limit doesn't exist.
12. Ans:(B) Limit doesn't exist.
Find out:
where,
If all of above three are equal upon applying limit, then limit exists.
When x < 1 -> 1-1 = 0
When x = 1 -> 8
When x > 1 -> 7 + 1 = 8
ALL of the THREE must be equal. As they are not equal. 0
8; hence, limit doesn't exist.
13. Ans:(D) -∞; x = 9
Given function:
The derivative would be:
=>
=>
=>
Now at x = 7:
=>
2. Ans:(B) 3
Given function:
The derivative would be:
=>
=>
=>
Now at x = 4:
=>Ans:
3. Ans:(D) -5
Given function:
The derivative would be:
or
=>
=>
Now at x = -1:
=>
=> Ans:
4. Ans:(C) 7 divided by 9
Given function:
The derivative would be:
or
=>
=>
Now at x = -3:
=>
=> Ans:
5. Ans:(C) -8
Given function:
Now if we apply limit:
=>
=> Ans:
6. Ans:(C) 9
Given function:
Now if we apply limit:
=>
=> Ans:
7. Ans:(D) doesn't exist.
Given function:
In this case, even if we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.
Check:
If you apply the limit, answer would be infinity.
8. Ans:(A) Doesn't Exist.
Given function:
Same as Question 7
If we try to simplify it algebraically, there would ALWAYS be x power something (positive) in the denominator. And when we apply the limit approaches to 0, it would always be either + infinity or -infinity. Hence, Limit doesn't exist.
9, 10.
Please attach the graphs. I shall amend the answer. :)
11. Ans:(A) Doesn't exist.
First We need to find out:
If both sides are equal on applying limit then limit does exist.
Let check:
If x
If x
Since both are not equal, as
12. Ans:(B) Limit doesn't exist.
Find out:
If all of above three are equal upon applying limit, then limit exists.
When x < 1 -> 1-1 = 0
When x = 1 -> 8
When x > 1 -> 7 + 1 = 8
ALL of the THREE must be equal. As they are not equal. 0
13. Ans:(D) -∞; x = 9
f(x) = 1/(x-9).
Table:
x f(x)=1/(x-9)
----------------------------------------
8.9 -10
8.99 -100
8.999 -1000
8.9999 -10000
9.0 -∞
Below the graph is attached! As you can see in the graph that at x=9, the curve approaches but NEVER exactly touches the x=9 line. Also the curve is in downward direction when you approach from the left. Hence, -∞, x =9 (correct)
14. Ans: -6
s(t) = -2 - 6t
Inst. velocity =
Therefore,
At t=2,
Inst. velocity = -6
15. Ans: +∞, x =7
f(x) = 1/(x-7)^2.
Table:
x f(x)= 1/(x-7)^2
--------------------------
6.9 +100
6.99 +10000
6.999 +1000000
6.9999 +100000000
7.0 +∞
Below the graph is attached! As you can see in the graph that at x=7, the curve approaches but NEVER exactly touches the x=7 line. The curve is in upward direction if approached from left or right. Hence, +∞, x =7 (correct)
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