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brilliants [131]
2 years ago
15

What is 1.75×10^8 in standard form

Mathematics
1 answer:
Bingel [31]2 years ago
8 0
In order to convert scientific notation to standard form, just move the decimal over however many places the exponent is. In this case you move it positively (to the right) 8 places to get 175,000,000
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Guided Practice
NARA [144]

Answer:

C.

1 ≤ w ≤ 5

Step-by-step explanation:

Move all terms not containing  

w

from the center section of the inequality.

Inequality Form:

1 ≤ w ≤ 5

Interval Notation:

[ 1 , 5 ]

4 0
3 years ago
Please answer ASAP. will give brainliest
Margarita [4]

12 × 12=144

12 × 20 = 240

240 + 144 = 384

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Step-by-step explanation:

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A rectangle is 40 yards long and 30 yards wide. What is the length of the diagonal that cuts through the center?
choli [55]

Answer:

it should be 50

Step-by-step explanation:

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3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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