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bagirrra123 [75]
3 years ago
9

A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations

of 5 friends could
possibly receive the tickets?
A. 13
B. 40
C. 56
b. 64​
Mathematics
1 answer:
allsm [11]3 years ago
6 0

_8C_5=\dfrac{8!}{5!3!}=\dfrac{6\cdot7\cdot8}{2\cdot 3}=56

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