<span>In this problem, to find the answer we have to setup a series of ratios that relate the scale to real life distance. We know that 1cm = 2.50km, so that ratio would be 1cm/2.5km. For two towns that are 4.75cm apart on the map, we set a ration of 4.75cm/x km, where x is the actual distance. Now we set the ratios equal to each other and solve for x. 1/2.5=4.75/x where x = 4.75*2.5/1 = 11.875 and rounding up we get 11.88 km. The two towns are actually 11.88 km apart from each other.</span>
<h3>
Answer: 5 < x < 29</h3>
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Explanation:
Since AB is smaller than AD, this must mean the angle ACB is smaller than angle ACD. Note how these angles are opposite the sides mentioned.
So 2x-10 < 48
At the same time, 2x-10 is also larger than 0.
Overall, we can say 0 < 2x-10 < 48
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Let's solve for x
0 < 2x-10 < 48
0+10 < 2x < 48+10 ...... add 10 to all sides
10 < 2x < 58
10/2 < x < 58/2 ..... divide all sides by 2
5 < x < 29
I cannot suggest anything other than the set of real numbers here, but maybe someone else can provide a better answer. As long as you increase or decrease x (which is a real number) then you will get a real number, or the infinite set of real numbers.
<span>let n+2=u
so, the equation became= [2/u]-[3/u]=5
=> [(2+3)/u]=5
=> 5/u=5
=> u=5/5=1
thus, u=1
we know u=n+2
so, n+2=1
=> n=1-2=-1
so, n=-1</span>
Answer:
+ 3
+ 2x
Step-by-step explanation:
x(x^2 + x + 2x + 2)
x ( x^2 + 3x + 2)
+ 3
+ 2x