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Mice21 [21]
3 years ago
10

3(x-1)=2x+9 help me :(

Mathematics
2 answers:
Flura [38]3 years ago
7 0
3(x - 1) = 2x + 9
3x - 3 = 2x + 9
3x (-2x) -3 (+3) = 2x (-2x) + 9 (+9)
(3x -2x) = (9 + 9)
(x) = (18)
x = 18

x = 18          is your answer

hope this helps
dezoksy [38]3 years ago
7 0
Here's the way to get the answer.

1) 3x - 3 = 2x + 9
+3 +3

2) 3x = 2x + 12
-2x -2x

3) x = 12


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Given:

A number when divided by 780 gives remainder 38.

To find:

The reminder that would be obtained by dividing same number by 26.

Solution:

According to Euclis' division algorithm,

a=bq+r                ...(i)

Where, q is quotient and 0\leq r is the remainder.

It is given that a number when divided by 780 gives remainder 38.

Substituting b=780,\ r=38 in (i), we get

a=(780)q+38

So, given number is in the form of 780q+38, where q is an integer.

On dividing 780q+38 by 26, we get

\dfrac{780q+38}{26}=\dfrac{780q}{26}+\dfrac{38}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26+12}{26}

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\dfrac{780q+38}{26}=30q+1+\dfrac{12}{26}

Since q is an integer, therefore (30q+1) is also an integer but \dfrac{12}{26} is not an integer. Here 26 is divisor and 12 is remainder.

Therefore, the required remainder is 12.

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