If B is a point AC and AB:BC = 1:2, what are the coordinates of B?
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Answer: 352
Step-by-step explanation:
To find the Lateral area of a square pyramid , we will follow the three steps below:
1. Find the perimeter of the base
2. Multiply the perimeter by the slant height
3. Divide the result above by 2
That is :
The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.
Applying the formula above:
1. The base is a square , therefore the perimeter of a square is 4L , That is
Perimeter = 4(8)
Perimeter = 32m
2. Perimeter x slant height , that is
32 x 22 = 704m
3. Dividing the result by 2 , we have :
704/2 = 352
Therefore , the Lateral area of the pyramid is 352
36(3.14) = 4/3 x 3.14 x r^3
113.04 = 4.187(r^3)
113.04/4.187 = r^3
26.997 = r^3
3√26.997 = r
r = ~3
Check: 3^3(
)(4/3) = 27(3.14)(4/3) = 113.04
113.04 = 4.187(r^3)
113.04/4.187 = r^3
26.997 = r^3
3√26.997 = r
r = ~3
Check: 3^3(