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Lerok [7]
3 years ago
6

George walks 11 mile to school. He leaves home at the same time each day, walks at a steady speed of 33 miles per hour, and arri

ves just as school begins. Today he was distracted by the pleasant weather and walked the first 1212 mile at a speed of only 22 miles per hour. At how many miles per hour must George run the last 1212 mile in order to arrive just as school begins today?
Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
You divide 33/11 to get to then 1212/22 to get fifty five fifty firve minus to is fifty three your anser is fifty three
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What is x=.30(729). explain
dsp73

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x = 218.7

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3 years ago
At noon a passenger train leaves the Dupont Railway station and travels due east for 2 hours. At 12:45 pm the same day a second
kati45 [8]

Answer:

<em>The speed of the first train is 70 km/hr</em>

<em>The speed of the second train is 60 km/hr</em>

Step-by-step explanation:

For the first train:

Travel time = 2 hours

The speed = ?

we designate the speed as V

For the second train:

The travel time = 1 hr 15 min = 1.25 hrs (15 minutes = 15/60 hrs)

speed = 10 km/hr slower than that of the first train, we can then say

the speed = V - 10

The total distance traveled by both trains in the opposite direction of one another is 215 km

we can put this problem into an equation involving the distance covered by the trains.

we know that distance = speed x time

the distance traveled by the first train will be

==> 2 hrs x V = 2V

the distance traveled by the second train will be

==> 1.25 hrs x (V - 10) = 1.25(V - 10)

Equating the above distances to the total distance between the trains, we'll have

2V + 1.25(V - 10) = 215

2V + 1.25V - 12.5 = 215

3.25V = 215 + 12.5

3.25V = 227.5

V = 227.5/3.25 = <em>70 km/hr     this is the speed of the first train</em>

Recall that the speed of the second train is 10 km/hr slower, therefore

speed of the second train = 70 - 10 = <em>60 km/hr</em>

4 0
3 years ago
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