Calculator estimates 4/13 is .3076 and 3/10 to be .3 so 4/13 is larger
3/10 is rational because decimal can be predicted unlike 4/13 which keeps going

5 0

3 years ago

What is the slope of a line perpendicular to the following line?<br><br> <img src="https://tex.z-dn.net/?f=-7y%2B%208x%3D9" id="

EleoNora [17]

Answer:

m = $-\frac{7}{8}$

Step-by-step explanation:

<h3>Finding the slope of the given line </h3>

We need to find the slope of this equation to find the slope of a line perpendicular to it. This means we must solve for y.

Start off by subtracting 8x from both sides of the equation to start isolating the variable y.

$-7y=9- 8x$

Now solve for y by dividing both sides of the equation by -7.

$y=\frac{9-8x}{-7}$

This can be broken into two parts by distributing the negative sign from the -7 into the 9 and -8x like so:

$y=\frac{-9}{7} +\frac{8x}{7 }$

The slope of a line is the coefficient of x, so in this case the slope of the given line ( $-7y+8x=9$ ) is $\frac{8}{7}$ .

<h3>Finding the slope of a line perpendicular to the given line</h3>

Two lines that are perpendicular would have opposite reciprocal slopes, which means the perpendicular slope would be the negative counterpart and would be flipped.

For example, if you have 2 as the slope of one of the perpendicular lines, the other line would be the opposite (-2) reciprocal ( $-\frac{1}{2}$ ).

Therefore, since we have the slope of one of the perpendicular lines (the given line), we would find the opposite reciprocal of it's slope to solve this problem.

Slope: $\frac{8}{7}$

Opposite: $-\frac{8}{7}$
Reciprocal: $-\frac{7}{8}$

The slope of the line perpendicular to $-7y+8x=9$ is $-\frac{7}{8}$ .

3 0

4 years ago