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hichkok12 [17]
3 years ago
12

Divide 2x³-3x²+5x-7 by x-2​

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
6 0

Answer: p(1/2)=11/2p(a)=a.

Step-by-step explanation:

valkas [14]3 years ago
3 0

<em>Answer:</em>

<em></em>

<em>        2x3 - 5x2 + 2x - 7</em>

<em>  ——————————————————</em>

<em>        x - 2       </em>

<em>Step-by-step explanation:            2x3 - 5x2 + 2x - 7</em>

<em> Simplify   ——————————————————</em>

<em>                  x - 2       </em>

<em>Checking for a perfect cube :</em>

<em> 3.1    2x3 - 5x2 + 2x - 7  is not a perfect cube</em>

<em></em>

<em>Trying to factor by pulling out :</em>

<em> 3.2      Factoring:  2x3 - 5x2 + 2x - 7 </em>

<em></em>

<em>Thoughtfully split the expression at hand into groups, each group having two terms :</em>

<em></em>

<em>Group 1:  2x - 7 </em>

<em>Group 2:  2x3 - 5x2 </em>

<em></em>

<em>Pull out from each group separately :</em>

<em></em>

<em>Group 1:   (2x - 7) • (1)</em>

<em>Group 2:   (2x - 5) • (x2)</em>

<em></em>

<em>Bad news !! Factoring by pulling out fails :</em>

<em></em>

<em>The groups have no common factor and can not be added up to form a multiplication.</em>

<em></em>

<em>Polynomial Roots Calculator :</em>

<em> 3.3    Find roots (zeroes) of :       F(x) = 2x3 - 5x2 + 2x - 7</em>

<em>Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  </em>

<em></em>

<em>Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers</em>

<em></em>

<em>The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient</em>

<em></em>

<em>In this case, the Leading Coefficient is  2  and the Trailing Constant is  -7.</em>

<em></em>

<em> The factor(s) are:</em>

<em></em>

<em>of the Leading Coefficient :  1,2</em>

<em> of the Trailing Constant :  1 ,7</em>

<em></em>

<em> Let us test ....</em>

<em></em>

<em>   P    Q    P/Q    F(P/Q)     Divisor</em>

<em>      -1       1        -1.00        -16.00     </em>

<em>      -1       2        -0.50        -9.50     </em>

<em>      -7       1        -7.00        -952.00     </em>

<em>      -7       2        -3.50        -161.00     </em>

<em>      1       1        1.00        -8.00     </em>

<em>      1       2        0.50        -7.00     </em>

<em>      7       1        7.00        448.00     </em>

<em>      7       2        3.50        24.50     </em>

<em></em>

<em>Polynomial Roots Calculator found no rational roots</em>

<em></em>

<em>Polynomial Long Division :</em>

<em> 3.4    Polynomial Long Division</em>

<em>Dividing :  2x3 - 5x2 + 2x - 7 </em>

<em>                              ("Dividend")</em>

<em>By         :    x - 2    ("Divisor")</em>

<em></em>

<em>dividend     2x3  -  5x2  +  2x  -  7 </em>

<em>- divisor  * 2x2     2x3  -  4x2         </em>

<em>remainder      -  x2  +  2x  -  7 </em>

<em>- divisor  * -x1      -  x2  +  2x     </em>

<em>remainder              -  7 </em>

<em>- divisor  * 0x0                 </em>

<em>remainder              -  7 </em>

<em>Quotient :  2x2 - x </em>

<em>Remainder :  -7 </em>

<em></em>

<em>so x=-7</em>

<em></em>

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