Answer:
C
Explanation:
Turner Syndrom individuals have an aneuploidy (Cells with abnormal chromosome numbers), their sex cells only have one X chromosome.
Paternal genetic apportation is, in this case, XB (Because Tom has normal vison), Jill genotipic is XBXb (Color Blindness is recessive, Xb is not expressed on her fenotipic because the dominant XB make her has normal vision).
Tom only has sperm carrying XB chromosomes because he has normal vision.
Jill Ovules are XB or Xb, She has both alleles.
An Jill's ovule carring the Xb mutante allele is fertilized by sperm lacking sex chromosomes. As a result their Daughter is born withTurner Syndrom and Color Blindness.
This sperm lacking sex chromosomes is the result of a Paternal nondisjunction of sex chromosomes during meiosis
"Bonus"
As color blindness is a X-linked recessive disorder, this case is one of the fewer scenarios when Jim and Tom can have a Daughter with Color Blindness. In a normal case their outspring has these possibilities of having Colorblindness...
Genetic Cross
Jill x Tom
(XBXb x XBY0)
Genotipic Fenotipic
XBXB 25% Females with normal vision
XBXb 25% Females with normal vision
XBY0 25% Males with normal vision
XbY0 25% Males with Color Blindness
75% of their children will have normal vision
100% of females will have normal vision
50% of males will have normal vision
Only males, 50% of them, will have Color Blindness.
