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sesenic [268]
3 years ago
15

Do the ratios 10:9 and 17:15 form a proportion?

Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

Nope! these ratios do not form a proportion

Step-by-step explanation:

if you use a calculator to divide 10/9, you get 1.111 repeating.

if you use a calculator to divide 17/15, you get 1.133 repeating.

<em>since 1.111 does not equal 1.113, </em><em>these ratios are not proportional. </em>

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lapo4ka [179]
2.485 is round to 450 and 450 divide by 15 equals 30. 485 divide by 15 32 r 5
4 0
3 years ago
100 points and brainliest
nordsb [41]

Answer: Hello Luv......

Hope this helps. Mark me brianest please... Anna ♥

Step-by-step explanation:

Answer: -40 < T < 140

From the question, we are informed that the gas that the driver uses freezes at −40° F and evaporates at 140° F.

To get the inequality to represent the temperatures at which the gas in the truck will remain in liquid form, we should note that the temperature will be lower than 140°F but more than -40°F. This can be expressed as:

= -40 < T < 140

6 0
3 years ago
Read 2 more answers
A plumber charges $50 to come to a house and $20 an hour for work time.
PolarNik [594]
Since the 50 remains the same every time, is has no letters next to it in the equation.  The 20, however, is multiplied by the amount of hours, and will therefore have an h next to.  

20h + 50- the answer is a. 
6 0
3 years ago
Ian has 120 folders to file. So far, he has filed 36 of the folders. What percent of the folders does he have left to file?
balandron [24]
120-36 = 84 <==== what he has left

84/120×100% = percentage of what he has left
70% = percentage aka answer.
8 0
4 years ago
Read 2 more answers
Find the lateral area of the figure geometry
Arlecino [84]

Answer:

  • A) 420 in²

Step-by-step explanation:

The lateral surface area excludes the area of top and bottom faces.

Given is the right pentagonal prism with side length of 7 in and height of 12 in.

<u>The lateral area is:</u>

  • L = Ph = 5*7*12 = 420 in²

Correct choice is A

6 0
3 years ago
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