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3 years ago

Will mark brainiest help

Mathematics

2 answers:

alex41 [277]3 years ago

5 0

Answer:

What do you need help with?

Step-by-step explanation:

uranmaximum [27]3 years ago

4 0

Answer:

Step-by-step explanation:

theres no picture or file

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Part B

galina1969 [7]

Answer:

This graph does not represent a function. Two points where it fails the vertical line test are (0, 0) and (0, 1).

Step-by-step explanation:

This is the exact answer edumentum gave me. be careful, i got this wrong.

4 0

3 years ago

A parallelogram with congruent diagonals is a _____.

Advocard [28]

An example of a parallelogram with congruent diagonals is a square.

Hope this helps =)

7 0

4 years ago

David drops a soccer ball off a building. The building is 75 meters tall.

Nezavi [6.7K]

a) 70.1 m

The ball is moving by uniformly accelerated motion, with constant acceleration $g=9.8 m/s^2$ (acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation

$h(t)=h_0 - \frac{1}{2}gt^2$

where $h_0 = 75 m$ is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:

$h(1 s)=75 m - \frac{1}{2}(9.8 m/s^2)(1 s)^2=70.1 m$

b) 3.9 s

We can still use the same equation we used in the previous part of the problem:

$h(t)=h_0 - \frac{1}{2}gt^2$

This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have

$0=h_0 - \frac{1}{2}gt^2$

And solving for t we find

$t=\sqrt{\frac{2h_0}{g}}=\sqrt{\frac{2(75 m)}{9.8 m/s^2}}=3.9 s$

8 0

3 years ago

Find the value of M, to the nearest tenth

a_sh-v [17]

Answer:

m = 18*sin(43)

7 0

3 years ago

Read 2 more answers

A circle has a radius of \sqrt{13}√ 13 square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le

timofeeve [1]

Answer: The equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

$(x-h)^2+(y-k)^2=r^2.$

In the given circle,

radius, r = √13 units and center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

$(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.$

Thus, the equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

7 0

3 years ago