2 years ago

#2) Can the sides of a triangle have the lengths 1, 3, 1? * O Yes O No

1 answer:

8 0

Yes it would be an isosceles triangle

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Iteru [2.4K]

There is no solution it’s in final form

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3 years ago

stiv31 [10]

7,000,000+80,000+200+80+7

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EleoNora [17]

Is there a way you can do this in English like write it in English?

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2 years ago

myrzilka [38]

Answer:

$-7x^2+x+9=-6x$

$-7x^2+x+9+6x=-6x+6x$

$-7x^2+7x+9=0$

$quadratic\: formula$

$x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\left(-7\right)\cdot \:9}}{2\left(-7\right)}$

$\sqrt{-7^{2} -4(-7)\times9} =\sqrt{301}$

$x_{1,\:2}=\frac{-7\pm \sqrt{301}}{2\left(-7\right)}$

$\frac{-7+\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7+\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7+\sqrt{301}}{-14}$

$\frac{-7-\sqrt{301}}{2\left(-7\right)}$

$=\frac{-7-\sqrt{301}}{-2\cdot \:7}$

$=\frac{-7-\sqrt{301}}{-14}$

$answer=\frac{7+\sqrt{301}}{14}$

$OAmalOHopeO$

7 0

2 years ago

mojhsa [17]

Go to g o o g l e
translate is the answer

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2 years ago