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3 years ago

#2) Can the sides of a triangle have the lengths 1, 3, 1? * O Yes O No

Mathematics

1 answer:

Oduvanchick [21]3 years ago

8 0

Yes it would be an isosceles triangle

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What is the mean of the values in the stem-and-leaf plot?

prisoha [69]

Answer:

You're answer is 42

Step-by-step explanation:

if you add all the numbers together, you would get 336. since there are eight numbers in the data set, you should divide it by eight.. with that said, 336/8 is 42

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2 years ago

Solve the inequality for u.<br> 7u - 32< - 3(6-3u)<br> Simplify your answer as much as possible.

Dmitry_Shevchenko [17]

Answer:

u > - 7

Step-by-step explanation:

7u - 32 < - 3(6-3u)

7u - 32 < - 18 + 9u

18-32 < - 7u + 9u

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2 years ago

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Solve the system of equations using the linear combination method.

IceJOKER [234]

J=25/5+7 and those are your answers i hope i helped
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3 years ago

What does a regression line really tell us? There are actually four things it can tell us, but I only need you and your group to

andrew-mc [135]

Answer:

Here is one idea:

You can use a regression line to predict what will happen at a time not given by your data. You can use it to make predictions about future times.

Here is another one:

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Try to come up with one of your own so you can have three. :)

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3 years ago

How do you solve cos(pi/24) using Half-Angle formulas, and leaving in simplified form?

adoni [48]

$\cos \frac{\theta}{2}=\sqrt{\frac{1+\cos \theta}{2}}
\\
\\ \cos{\frac{\pi}{24}}=\cos{\frac{\frac{\pi}{12}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{12}}{2}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } 
\\
\\ \cos{\frac{\pi}{12}}=\cos{\frac{\frac{\pi}{6}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{6}}{2}}= \sqrt{ \frac{1}{2}+ \frac{ \frac{ \sqrt{3} }{2} }{2} } =\sqrt{ \frac{2}{4}+ \frac{ \sqrt{3} }{4} } = \sqrt{\frac{ 2+\sqrt{3} }{4} } = 
\\
\\ =\frac{ \sqrt{2+\sqrt{3}} }{2} 
$

$\cos{\frac{\pi}{24}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } = \sqrt{ \frac{1}{2}+ \frac{\frac{ \sqrt{2+\sqrt{3}} }{2}}{2} } = \sqrt{ \frac{2}{4}+ \frac{ \sqrt{2+\sqrt{3}} }{4}} } =\sqrt{ \frac{ 2+\sqrt{2+\sqrt{3}} }{4}} } 
\\
\\\cos{\frac{\pi}{24}}=\frac{\sqrt{2+\sqrt{2+\sqrt{3}}}} {2}$

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3 years ago