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AysviL [449]
3 years ago
14

Needed now PLEASE HELP ME FOR BRAINIEST on a graph what does the solution of a system of equations look like.

Mathematics
1 answer:
siniylev [52]3 years ago
7 0
On a graph with two or more different lines representing the two or more different equations in a system of equations, the solution to the system of equations is the point at which the different lines intersect.

Hope this helps!
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A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1
Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth= \$ 17,000

depreciates by \frac{1}{2} in 3 years.

time=  19 years

depreciates rate=?

Using formula:

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

\to A_t=A_0(1-\frac{r}{100})^t

calculates depreciate value in 3 year = \frac{1}{2} \times 17,000

                                                              = 8,500

so,

A_t=8,500\\\\A_0=17,000\\\\t=3\ years

\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%

depreciates rate= 20%

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238

4 0
3 years ago
Read 2 more answers
1/2 s + 3/4 s + 1/4 s + 4
Doss [256]

1/2 s + 3/4 s + 1/4 s + 4

((2+3+1)/4)s +4

6/4 s + 4

3/2 s + 4

4 0
3 years ago
Read 2 more answers
Write the expression for when you translate the graph of y = |3x− 5| one unit to the right. Plzz help
AfilCa [17]

Answer:

2<x<4/3

Step-by-step explanation:

Given the equation of a graph to be y = |3x− 5|, if the equation is one unit to the right, this can be expressed as |3x-5| > 1.

Solving the resulting equation

|3x-5| > 1.

Since the function 3x-5 is in a modulus sign, this means that the function can take both negative and positive values.

For positive value of the function;

+(3x-5) > 1

3x > 1+5

3x>6

x>6/3

x>2 ... (1)

For the negative value of the function;

-(3x-5) > 1

On expansion

-3x+5 > 1

-3x > 1-5

-3x > -4

Multiplying through by -1 will also change the inequality sign

x < -4/-3

x < 4/3...(2)

Combining equation 1 and 2, we have;

2<x<4/3

6 0
3 years ago
Read 2 more answers
Need help...with this graph
Lady_Fox [76]

Answer:

The graph with coordinates x6,y8

Step-by-step explanation:

7 0
3 years ago
Find the length of the arc round your answer to the nearest 10th
son4ous [18]

Answer:

Step-by-step explanation:

3 0
3 years ago
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