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Bogdan [553]
2 years ago
13

On July 16, 1882, a massive thunderstorm over Dubuque, Iowa, produced huge hailstones. The diameter of some of the hailstones wa

s 17 in. Ice weighs about 0.033 lb/in3. What is the approximate weight of a 17 in. hailstone
Mathematics
1 answer:
Rufina [12.5K]2 years ago
7 0
Id say 0.187 because 0.033 times 17. then that number divided by 3
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4-[6(3x+2)-x]+4 order of operations
weqwewe [10]

Answer:

-4 - 17x

Step-by-step explanation:

Anything enclosed in parentheses must be done first if possible.  (3x + 2) is inside two sets of parentheses, but nothing can be done with 3x + 2.  

Multiplication must be done next.  [6(3x+2)-x] becomes 18x + 12 - x, or

17x + 12.

Now we have 4 - 17x - 12 + 4.  Combining like terms through addition and subtraction, we get 4 - 12 + 4 - 17x, or -4 - 17x.

3 0
3 years ago
Simplify fully: (Question is on the photo).
dedylja [7]

Step-by-step explanation:

4(x + 3) {z}^{ - 1}

6 0
3 years ago
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3x + y = 5<br><br> 2x - 2y = -2
Vesnalui [34]

Answer:

Solving the system of equations:

x: 1

y: 2

Step-by-step explanation:

Plug it in to see if it is right, to make sure of course.  Better to be safe than sorry.

7 0
2 years ago
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Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Ram is 3 times old as his son and the sum of their age is 48.how old is each?
stich3 [128]

Answer:

12 and 36

Step-by-step explanation:

x+3x=48

4x=48

divide by 4

x=12

48-12=36

6 0
3 years ago
Read 2 more answers
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