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The coordinates for the pre-image are P(1,3), Q(4,4), R(4,1), and S(1, -1).
The transformation is 4 units left, and 4 units down.
That means we must subtract 4 units to x-coordinates, and subtract 4 units from y-coordinates. So, the image has coordinates P'(-3,-1), Q'(0,0), R'(0, -3), and S'(-3, -5).
The image below shows the image and pre-image.
Answer:
Graphs 1, 2, and 3 are not functions. Graph 4 is a function.
Step-by-step explanation:
Use the vertical line test.
Imagine a vertical line moving from left to right.
If in any position of the vertical line, it intersects more than one point on the graph, then it is not a function.
In graphs 1 and 2 it is clear that there are many vertical lines than would intersect the graph at more than one point.
In graphs 3, a vertical line would intersect the vertical parts of the graph at more than 1 point, so graph 3 is not a function.
The only function is graph 4.
2. 5(x-1)=-3x+35
5x-5=-3x+35
5x=-3x+30
2x=30
x=15
2l + 2w = 16
2(l + w) = 16
l + w = 8
Lengths could be any numbers greater than 0 and less than 8
0 < l < 8
