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KengaRu [80]
3 years ago
10

Each answer choice below shows an equation and a value for x. Which of the following are true? Select three that apply.

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

Replace x in each equation and see which ones are true.

The answers are:

C. If 5x + 10 =20 then x =2

D. If 6x-12=48, then x=10

F. If 8x(x-4)=32, then x=8

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6th grade math plz help
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Answer:

The question needs more information but you can see that all the numbers in the 1st column are multiplied by 6 to equal the number in column 2

Step-by-step explanation:

3 x6 =18

6 x 6= 36

9 x6= 54

12 x6 =72

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3 years ago
The length of a rectangle with area 38 in2 depends on its width. Write the formula that describes the length of the rectangle as
Ostrovityanka [42]

Answer:

L = 38/W

Step-by-step explanation:

The area of a rectangle is computed by multiplying length by width. For length L and width W in inches, your rectangle has area ...

A = LW

38 = LW

Then the length can be found by dividing the equation by W:

L = 38/W

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3 years ago
Extended rotation rules
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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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3 years ago
What is the chemical formula for the molecule modeled?
adelina 88 [10]
The correct answer is A
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