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3 years ago

Which facts could be applied to simplify this expression?Ckeck all that apply 5x+3y+(-x)+6z

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

A, C, and D

Step-by-step explanation:

I just took the test.

kenny6666 [7]3 years ago

4 0

Answer:

5x+3y+(-x)+6z

5x+(-x)+3y+6z

4x+3y+6z

The facts to apply is PEMDAS which is parenthesis,exponents, multiplication,division,addition and subtraction.

Then group like terms if there are any.

You finally get to a simplified answer if there are no like terms

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The circle below is centered at the origin and has a radius of 4. What is its equation?

Alecsey [184]

Answer:

C) x^2 + y^2 = 16

Step-by-step explanation:

<h2><u>Find the equation </u></h2>

since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :

place the horizontal line of the radius where y = 0 .

this means that if y = 0 , then x = 4

therefore :

x^2 + y^2

4^2 + 0^2

= 16

<h3><u>hence the answer is C ) x^2 + y^2 = 16</u></h3>

7 0

3 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

Salsk061 [2.6K]

Answer:

$(-\infty, 0.2661)$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

n=60 represent the sample size

X=12 represent the number of masks that had lenses pop out at 250°

$\hat p =\frac{12}{60}=0.2$ represent the estimated proportion of masks that had lenses pop out at 250°

p represent the population proportion of masks that had lenses pop out at 250°

Confidence =0.9 or 90%

$\alpha=0.1$ represent the significance level

Confidence interval

On this case we want a interval on this form : $(-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})$

So the critical value would be on this case $z_{\alpha}=1.28$ and we can use the following excel code to find it: "=NORM.INV(1-0.1,0,1)"

We found the lower limit like this:

$0.2 +1.28\sqrt{\frac{0.2 (1-0.2)}{60}}=0.2661$

And the interval would be: $(-\infyt, 0.2661)$

3 0

4 years ago

Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}

Lady_Fox [76]

Answer:

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

Step-by-step explanation:

Given that:

$\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]$

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)]$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1]$

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

3 0

4 years ago

Matt's Ice Cream Shoppe has 7 cups of sprinkles to use on sundaes for the rest of the day. If each sundae is served with

igor_vitrenko [27]

I think it is 63 because 1/8 multiplied by 8 gives you 1 cup then multiply by 7 to give you the amount the company can sell

6 0

3 years ago

What is the solution set of x^2+y^2=26 and x-y=6

Strike441 [17]

$x^{2} + y^{2} =26 x-y=6 x=y+6
 Replacing in equation; (y+6[tex] )^{2}$ + $y^{2}$ =26
$y^{2} +12x+36+ y^{2} =36$
= $2y^{2} +12x+36-26=0$
= $2y^{2} +12x+10=0$
Product = 12
Sum= 10
factoring;
2 $y^{2}$ +2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1

4 0

4 years ago

Read 2 more answers