Ask question

Ask question

All categories

2 years ago

7

In a quadrilateral ABCD, AB ∥ DC and AD ∥ BC . Find the perimeter of ΔCOD if the diagonals of the quadrilateral intersect each o

ther at point O and AC = 20 in, BD = 20 in, AB = 13 in.

1 answer:

SVEN [57.7K]2 years ago

5 0

Answer Perimeter = 33in

Step-by-step explanation:

AC = 20

BD = 20

AB = 13

O is the midpoint

OD = OC = 20/2 = 10

AB = DC = 13 in

P = DC + OD + OC = 13+10+10 = 33in

You might be interested in

Police use photographs of various facial features help witnesses identify suspects. One basic identification kit contains 195 ha

Brrunno [24]

Answer: 99 different faces

Step-by-step explanation:

Since a witness can clearly remember the hairline and the eyes and eyebrows of a suspect, and the

basic identification kit contains 195 hairlines, 99 eyes and eyebrows, the number of different faces that can be produced with this information will be 99

5 0

2 years ago

WILL GIVE BRAINLIEST anitas and caseys bills do not vary from month to month. anita pays 80 more than casey does each month. ove

Mrac [35]

Answer:

1520/4=380 per month

Step-by-step explanation:

8 0

1 year ago

Elapsed time in minutes<br> Start time 3:10pm <br> end time 4;00pm

gizmo_the_mogwai [7]

50 minutes has elapsed.

6 0

2 years ago

What is 9/10 + 7/15

Yakvenalex [24]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}$

$\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}$

$\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}$

$\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}$

$\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}$

$\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}$

$\mathsf{= \dfrac{27+14}{30}}$

$\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}$

$\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}$

$\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

6 0

1 year ago

Read 2 more answers

Another geometry question for transition math! Please help me!

Nesterboy [21]

Answer:

The measure of <TRU is 72 deg.

Step-by-step explanation:

<QRU is a right angle, so it measures 90 deg.

Since m<QRT = 18 deg, then m<TRU must be 72 deg since 72 + 18 = 90.

Answer: The measure of <TRU is 72 deg.

6 0

2 years ago