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Delvig [45]
3 years ago
9

Estimate the square root to the nearest integer. Square root of 48

Mathematics
2 answers:
anzhelika [568]3 years ago
6 0
Answer~
7
Problem~
7x7=49
The nearest integer is 7
Airida [17]3 years ago
4 0
The square root to the nearest integer is 7 because 7 times 7 is 49
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What is X^2 -8x+9=0 written in the form(x-P)^2 =q?
Olenka [21]
x^{2} -8x+9=0
x^{2} -8x=-9
x^{2} -8x+16=-9+16
(x-4)^{2}=7


8 0
4 years ago
Write the equation in Slope - intercept form by solving for y. 2x+3y=12
Gennadij [26K]

y=-2/3x+4 i hope this helps!

7 0
3 years ago
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A designer wants to create an apartment in the shape of a right triangle as his new design. If he has three partitions that are
ella [17]

No, he can not do it

Step-by-step explanation:

To prove that the the given three sides can form a right triangle:

  1. Square the three sides
  2. Add the squares of the smaller two sides
  3. If the sum is equal to the square of the largest side, then the three given sides can form a right triangle
  4. If the sum is not equal to the square of the largest side, then the three given sides can not form a right triangle

∵ The designer has three partitions that are 14 , 9 and 20 feet

- Square the length of each partition

∵ 9² = 81

∵ 14² = 196

∵ 20² = 400

- Add the squares of the two smaller partitions 9 and 14

∵ 81 + 196 = 277

∵ The square of the largest partition = 400

∵ 277 ≠ 400

∴ The sum of the squares of the two smaller partitions is not

   equal to the square of the third partition

- To create the apartment in the shape of a right triangle he must

   have three partitions the sum of the squares of the two smaller

   partitions is equal to the square of the largest partition

∴ He can not create the apartment in the shape of a right triangle

No, he can not do it

Learn more:

You can learn more about the right triangles in brainly.com/question/4098846

#LearnwithBrainly

3 0
3 years ago
If tan theta= 3/4 , find csc theta
dangina [55]

Answer:

csc\theta=\frac{5}{3}

Step-by-step explanation:

Given:

tan\theta =\frac{3}{4}

cot\theta =\frac{4}{3}                 [∵ cot\theta =\frac{1}{tan\theta} ]

Squaring both sides.

cot^2\theta =\frac{4^2}{3^2}=\frac{16}{9}

csc^2\theta -1=\frac{16}{9}        [∵ cot^2\theta =csc^2\theta-1] ]

Adding 1 to both sides.

csc^2\theta -1+1=\frac{16}{9}+1

csc^2\theta =\frac{16}{9}+1

csc^2\theta=\frac{16}{9} +\frac{9}{9}     [Taking LCD=9 and adding fractions ]

csc^2\theta=\frac{16+9}{9}

csc^2\theta=\frac{25}{9}

Taking square root both sides.

\sqrt{csc^2\theta}=\sqrt{\frac{25}{9}}

∴ csc\theta=\frac{5}{3}

6 0
3 years ago
Vamos a ver.... A mi me gusta una chica, ella se ríe conmigo me dibuja la mesa de todo y todo el rato habla más conmigo q con na
max2010maxim [7]

Step-by-step explanation:

Puede que si pero espera un poco para que ella se te confiese

7 0
3 years ago
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