Consider the equation 1/3x−2=x+2. Write a system of linear equations using each side of the equation. Then solve the original eq
1 answer:
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Answer:
$800,500 (nearest dollar)
Step-by-step explanation:
The given scenario can be modeled as an <u>exponential equation</u>.
<u>General form of an exponential function</u>:
where:
- a is the initial value (y-intercept)
- b is the base (growth/decay factor) in decimal form
- x is the independent variable
- y is the dependent variable
If b > 1 then it is an increasing function
If 0 < b < 1 then it is a decreasing function
The initial value (a) is the value of the investment.
Therefore, a = 1,000,000.
If the investment <u>decreases</u> by 2.2% each year, then it will be 97.8% of the previous year.
Therefore, b = 97.8% = 0.978.
Substitute these values into the formula to create a general equation for the scenario:
(where x is the time, in years).
To find the value of the investment after 10 years, substitute x = 10 into the formula:
Therefore, the value of the investment after 10 years is $800,500 (nearest dollar).
Learn more about exponential functions here:
The correct format of the question is
At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?
(A) 291
(B) 691
(C) 1040
(D) 1440
Answer:
The increase in the population at the end of 2009 is 291 people
Step-by-step explanation:
We are given the equation as
where
P = No of People
t= No of Years
it is given that in the year 2006 the population is 400
this will only happen when we take t= 0
so for
Year value of t
2006- t = 0
2007- t = 1
2008- t = 2
2009 t = 3
No of people in 2009 will be
= 400*1.728
P = 691.2
Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691
Increase = P(2009) - P(2006)
= 691 - 400
= 291
The increase in the population at the end of 2009 is 291 people.