First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:
7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.
In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°
In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°
I'm sorry, but just now, I don't know how to do the
third triangle in the question.
<span>16/20 is 80%.</span>
You find out by multiplying the denominator: 20 * 5 = 100
Then, you do the same to the numerator which is: 16 * 5 = x
So, x = 80%
Hope this helps! :D
Answer:
(32/15, -2/5)
Step-by-step explanation:
(1) ³/₂x - 2y = 4
(2) x + ⅓y = 2
(3) 3x - 4y = 8 Multiplied (1) by 2
(4) 3x + y = 6 Multiplied (2) by 3
5y = -2 Subtracted (3) from (4)
(5) y = -⅖ Divided each side by 5
x + ⅓(-⅖) = 2 Substituted (5) into (2)
x - ²/₁₅ = 2
x = 2 + ²/₁₅ Added ²/₁₅ to each side
x = 32/15
The system of equations has only one solution: (32/15, -2/5).
Answer:
Step-by-step explanation:
If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.
If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118
The answer is q=15
Hope this helps ya